Integrand size = 13, antiderivative size = 34 \[ \int \frac {2-\sin (x)}{2+\sin (x)} \, dx=-x+\frac {4 x}{\sqrt {3}}+\frac {8 \arctan \left (\frac {\cos (x)}{2+\sqrt {3}+\sin (x)}\right )}{\sqrt {3}} \]
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Time = 0.02 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {2814, 2736} \[ \int \frac {2-\sin (x)}{2+\sin (x)} \, dx=\frac {8 \arctan \left (\frac {\cos (x)}{\sin (x)+\sqrt {3}+2}\right )}{\sqrt {3}}+\frac {4 x}{\sqrt {3}}-x \]
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Rule 2736
Rule 2814
Rubi steps \begin{align*} \text {integral}& = -x+4 \int \frac {1}{2+\sin (x)} \, dx \\ & = -x+\frac {4 x}{\sqrt {3}}+\frac {8 \arctan \left (\frac {\cos (x)}{2+\sqrt {3}+\sin (x)}\right )}{\sqrt {3}} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.82 \[ \int \frac {2-\sin (x)}{2+\sin (x)} \, dx=-x+\frac {8 \arctan \left (\frac {1+2 \tan \left (\frac {x}{2}\right )}{\sqrt {3}}\right )}{\sqrt {3}} \]
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Time = 0.45 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.82
method | result | size |
default | \(-2 \arctan \left (\tan \left (\frac {x}{2}\right )\right )+\frac {8 \sqrt {3}\, \arctan \left (\frac {\left (2 \tan \left (\frac {x}{2}\right )+1\right ) \sqrt {3}}{3}\right )}{3}\) | \(28\) |
risch | \(-x +\frac {4 i \sqrt {3}\, \ln \left ({\mathrm e}^{i x}+2 i+i \sqrt {3}\right )}{3}-\frac {4 i \sqrt {3}\, \ln \left ({\mathrm e}^{i x}+2 i-i \sqrt {3}\right )}{3}\) | \(47\) |
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Time = 0.26 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.79 \[ \int \frac {2-\sin (x)}{2+\sin (x)} \, dx=\frac {4}{3} \, \sqrt {3} \arctan \left (\frac {2 \, \sqrt {3} \sin \left (x\right ) + \sqrt {3}}{3 \, \cos \left (x\right )}\right ) - x \]
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Time = 0.28 (sec) , antiderivative size = 42, normalized size of antiderivative = 1.24 \[ \int \frac {2-\sin (x)}{2+\sin (x)} \, dx=- x + \frac {8 \sqrt {3} \left (\operatorname {atan}{\left (\frac {2 \sqrt {3} \tan {\left (\frac {x}{2} \right )}}{3} + \frac {\sqrt {3}}{3} \right )} + \pi \left \lfloor {\frac {\frac {x}{2} - \frac {\pi }{2}}{\pi }}\right \rfloor \right )}{3} \]
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Time = 0.32 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.06 \[ \int \frac {2-\sin (x)}{2+\sin (x)} \, dx=\frac {8}{3} \, \sqrt {3} \arctan \left (\frac {1}{3} \, \sqrt {3} {\left (\frac {2 \, \sin \left (x\right )}{\cos \left (x\right ) + 1} + 1\right )}\right ) - 2 \, \arctan \left (\frac {\sin \left (x\right )}{\cos \left (x\right ) + 1}\right ) \]
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Time = 0.27 (sec) , antiderivative size = 51, normalized size of antiderivative = 1.50 \[ \int \frac {2-\sin (x)}{2+\sin (x)} \, dx=\frac {4}{3} \, \sqrt {3} {\left (x + 2 \, \arctan \left (-\frac {\sqrt {3} \sin \left (x\right ) - \cos \left (x\right ) - 2 \, \sin \left (x\right ) - 1}{\sqrt {3} \cos \left (x\right ) + \sqrt {3} - 2 \, \cos \left (x\right ) + \sin \left (x\right ) + 2}\right )\right )} - x \]
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Time = 7.73 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.06 \[ \int \frac {2-\sin (x)}{2+\sin (x)} \, dx=-x-\frac {8\,\sqrt {3}\,\mathrm {atan}\left (-\frac {\sqrt {3}\,\mathrm {tan}\left (\frac {x}{2}\right )-\sqrt {3}}{3\,\mathrm {tan}\left (\frac {x}{2}\right )+3}\right )}{3} \]
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